easter_date

(PHP 4, PHP 5, PHP 7, PHP 8)

easter_date — Restituisce un timestamp Unix della mezzanotte del giorno di Pasqua di un dato anno

Descrizione

easter_date(int $anno = ?): int

Restituisce il timestamp Unix corrispondente alla mezzanotte del giorno di Pasqua dell'anno specificato.

Dal PHP 4.3.0, il parametro anno è opzionale e ha come default l'anno corrente, se omesso.

Example #1 esempio di easter_date()

<?php

echo date("d M Y", easter_date(1999));        // 04 Apr 1999
echo date("d M Y", easter_date(2000));        // 23 Apr 2000
echo date("d M Y", easter_date(2001));        // 15 Apr 2001

?>

Avviso

Questa funzione gerererà un allarme (warning) se l'anno è fuori dall'escursione di validità dei timestamp UNIX (cioè prima del 1970 o dopo il 2037).

La data della Pasqua fu definita dal Concilio di Nicea nel 325 d.C. come la Domenica successiva alla prima luna piena dopo l'Equinozio di Primavera. Si assume che l'Equinozio cada sempre il 21 Marzo, quindi il calcolo si riduce alla determinazione della data della luna piena e la data della Domenica seguente. L'algoritmo qui usato fu proposto attorno all'anno 532 d.C. da Dionysius Exiguus (Dionigi il Piccolo). Nel Calendario Giuliano (for years before 1753) un semplice ciclo di 19 anni è usato per tracciare le fasi della Luna. Nel Calendario Gregoriano (per gli anni dopo il 1753 - ideato da Clavius e Lilius, e introdotto da Papa Gregorio XIII nell'Ottobre 1582, e in Gran Bretagna e nelle sue colonie nel Settembre 1752) due fattori correttivi sono aggiunti per rendere più accurato il ciclo.

(Il codice è basato su un programma in C di Simon Kershaw, <webmaster at ely.anglican dot org>)

Vedere easter_days() per il calcolo della Pasqua prima del 1970 o dopo il 2037.

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User Contributed Notes 6 notes

down

maxie ¶

16 years ago

To compute the correct Easter date for Eastern Orthodox Churches I made a function based on the Meeus Julian algorithm:



<?php

function orthodox_eastern($year) {

    $a = $year % 4;

    $b = $year % 7;

    $c = $year % 19;

    $d = (19 * $c + 15) % 30;

    $e = (2 * $a + 4 * $b - $d + 34) % 7;

    $month = floor(($d + $e + 114) / 31);

    $day = (($d + $e + 114) % 31) + 1;

    

    $de = mktime(0, 0, 0, $month, $day + 13, $year);

    

    return $de;

}

?>

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Alexander Bliznyuk ¶

7 years ago

Thank you, @Maxie, for algorythm for computing Orthodox Easter date.
It can be improved though. You added 13 days in order to map Julian calendar to Gregorian.  But 13 days is not a constant. It's an accumulated error fixed in Gregorian and should be calculated with this formula: (int)($year / 100) - (int)($year / 400) - 2

down

py dot lebecq at gmail dot com ¶

14 years ago

I recently had to write a function that allows me to know if today is a holiday.

And in France, we have some holidays which depends on the easter date. Maybe this will be helpful to someone.

Just modify in the $holidays array the actual holidays dates of your country.

<?php
/**
 * This function returns an array of timestamp corresponding to french holidays
 */
protected static function getHolidays($year = null)
{
  if ($year === null)
  {
    $year = intval(date('Y'));
  }
    
  $easterDate  = easter_date($year);
  $easterDay   = date('j', $easterDate);
  $easterMonth = date('n', $easterDate);
  $easterYear   = date('Y', $easterDate);

  $holidays = array(
    // These days have a fixed date
    mktime(0, 0, 0, 1,  1,  $year),  // 1er janvier
    mktime(0, 0, 0, 5,  1,  $year),  // Fête du travail
    mktime(0, 0, 0, 5,  8,  $year),  // Victoire des alliés
    mktime(0, 0, 0, 7,  14, $year),  // Fête nationale
    mktime(0, 0, 0, 8,  15, $year),  // Assomption
    mktime(0, 0, 0, 11, 1,  $year),  // Toussaint
    mktime(0, 0, 0, 11, 11, $year),  // Armistice
    mktime(0, 0, 0, 12, 25, $year),  // Noel

    // These days have a date depending on easter
    mktime(0, 0, 0, $easterMonth, $easterDay + 2,  $easterYear),
    mktime(0, 0, 0, $easterMonth, $easterDay + 40, $easterYear),
    mktime(0, 0, 0, $easterMonth, $easterDay + 50, $easterYear),
  );

  sort($holidays);
  
  return $holidays;
}
?>

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Guillaume Dufrene ¶

11 years ago

I found a problem with holidays timestamp computation and daylight saving time.
An article about it at http://goo.gl/76t31 (in french only, sorry).

In summary, this year (2013) easter begins before adding an hour for daylight saving time (occured sunday at 3:00). It means that if you do $easter + X, where x is a number of seconds equivalent to one day, 39 days or 50 days, the result is not equals to a midnight timestamp...

Here a function to check if a midnight timestamp is equals to an holiday :

function isHoliday( $ts ) {
// Licence : Creative Commons (BY)
// By Webpulser - http://goo.gl/76t31
  $fixed_holidays = array( ’01-01′, ’01-05′, ’08-05′, ’14-07′, ’15-08′, ’11-11′, ’25-12′ );
  $format = ‘d-m’;

 $dm = date($format, $ts);
  if ( in_array($dm, $fixed_holidays) ) return true;

 $easter = easter_date( date(‘Y’, $ts) );
  if ( date($format, $easter +   86400) == $dm ) return true;
  if ( date($format, $easter + 3369600) == $dm ) return true;
  if ( date($format, $easter + 4320000) == $dm ) return true;

 return false;
}

feel free to use / modify.

down

-1

phpuser ¶

20 years ago

The algorithm from Bigtree is correct if you add some (int) cast
<?php 
   function easter_date ($Year) { 
   
       /* 
       G is the Golden Number-1 
       H is 23-Epact (modulo 30) 
       I is the number of days from 21 March to the Paschal full moon 
       J is the weekday for the Paschal full moon (0=Sunday, 
         1=Monday, etc.) 
       L is the number of days from 21 March to the Sunday on or before 
         the Paschal full moon (a number between -6 and 28) 
       */ 
       

         $G = $Year % 19; 
         $C = (int)($Year / 100); 
         $H = (int)($C - (int)($C / 4) - (int)((8*$C+13) / 25) + 19*$G + 15) % 30; 
         $I = (int)$H - (int)($H / 28)*(1 - (int)($H / 28)*(int)(29 / ($H + 1))*((int)(21 - $G) / 11)); 
         $J = ($Year + (int)($Year/4) + $I + 2 - $C + (int)($C/4)) % 7; 
         $L = $I - $J; 
         $m = 3 + (int)(($L + 40) / 44); 
         $d = $L + 28 - 31 * ((int)($m / 4)); 
         $y = $Year; 
         $E = mktime(0,0,0, $m, $d, $y); 

         return $E; 

   } 
?>

down

-3

adwil at live dot com ¶

10 years ago

Hey, recently I needed a function to get realization dates in online shop, so here it is (ready to go for polish users, please adjust your dates for any other country):

<?php
function getWorkday($date1,$workDays) {
        $workDays = (int)$workDays;
        if ($workDays <= 0)
            return null;

        $date1=strtotime('-1 day',strtotime($date1));

        $lastYear = null;
        $hol=array('01-01','01-06','05-01','05-03','08-15','11-01','11-11','12-25','12-26');  //array of month-date of static holidays (these are from Poland)
        $i = 0;
        while ($i<=$workDays) {
            $year = date('Y', $date1);
            if ($year !== $lastYear){
                $lastYear = $year;
                $easter = date('m-d', easter_date($year));
                $date = strtotime($year . '-' . $easter); // easter
                $easterSec = date('m-d', strtotime('+1 day', $date)); // easter monday
                $greens = date('m-d', strtotime('+49 days', $date)); // zielone swiatki
                $cc = date('m-d', strtotime('+60 days', $date)); // boze cialo
                $hol[] = $easter;
                $hol[] = $easterSec;
                $hol[] = $greens;
                $hol[] = $cc;
            }
            $weekDay=date('w',$date1);
            if (!($weekDay==0 || $weekDay==6 || in_array(date('m-d',$date1),$hol)))
                $i++;

            $date1=strtotime('+1 day',$date1);
        }
        return date('Y-m-d',$date1);
    }
?>

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