ftp_site

(PHP 4, PHP 5, PHP 7, PHP 8)

ftp_site — Отправляет серверу команду SITE

Описание

ftp_site(FTP\Connection $ftp, string $command): bool

ftp_site() отправляет указанную команду SITE FTP-серверу.

Команды SITE не стандартизированы и зависят от FTP-сервера. Они могут быть полезны для изменения прав доступа к файлам или смены владельца или группы.

Список параметров

ftp: Экземпляр класса FTP\Connection.
command: Команда SITE. Обратите внимание, что этот параметр не проходит экранирование спецсимволов, так что могут возникнуть проблемы с именами, содержащими пробелы и прочие подобные символы.

Возвращаемые значения

Функция возвращает true в случае успешного выполнения или false, если возникла ошибка.

Список изменений

Версия	Описание
8.1.0	Параметр `ftp` теперь ожидает экземпляр класса FTP\Connection; раньше параметр ждал ресурс (resource).

Примеры

Пример #1 Отправка команды SITE FTP-серверу

<?php
// Соединение с FTP-сервером
$ftp = ftp_connect('ftp.example.com');
if (!$conn) die('Не удалось подключиться к ftp.example.com');

// Вход под именем "user" с паролем "pass"
if (!ftp_login($ftp, 'user', 'pass')) die('Не удалось войти на ftp.example.com');

// Отправка "SITE CHMOD 0600 /home/user/privatefile" FTP-серверу
if (ftp_site($ftp, 'CHMOD 0600 /home/user/privatefile')) {
   echo "Команда выполнена.\n";
} else {
   die('Команда не выполнена.');
}
?>

Смотрите также

ftp_raw() - Отправляет произвольную команду FTP-серверу

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Инструкция • Исправление • Сообщение об ошибке

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Примечания пользователей 6 notes

down

www.bossftp.com ¶

16 years ago

To send a SITE command and get the result, you can try this:



<?php

function ftpsite($conn, $cmd) {

    return ftp_raw($conn, "SITE $cmd");

}

?>

down

to at mail dot isec dot pt ¶

22 years ago

Hya, 
  Recently I had to work with FTP over PHP, since I didn't found any help about this topic I decided to post this here. If you need to chmod one file, I tested this on the ftp server using a ftp client and after I knew that the ftp server supported chmod I used the following commands:
$upload = ftp_put($conn_id, "/home/to/public_html/index.php", $source_file, FTP_ASCII);
$ch=@ftp_site($conn_id,"chmod 755 /home/to/public_html/index.php");

Hope this help!

T�

down

Anonymous ¶

23 years ago

site commands are extra-functionality provided by some ftp servers, and depend on the server : 

e.g. trying "ftp> site help" (with an interactive ftp client) on a proftp server would give :

 

214-The following SITE extensions are recognized:

 RATIO -- show all ratios in effect

 The following SITE commands are recognized (* =>'s unimplemented).

 HELP    CHMOD

214 Direct comments to admin@ftp.blahblah.fr



while with wu-ftpd on can typically get :



214-The following SITE commands are recognized (* =>'s unimplemented).

   UMASK           GROUP           INDEX           GROUPS

   IDLE            GPASS           EXEC            CHECKMETHOD

   CHMOD           NEWER           ALIAS           CHECKSUM

   HELP            MINFO           CDPATH                   

214 blabla



Unfortunately, ftp_site only returns true or false. It would be nice to have a way to get the server's reply in full : ftp_site('help') return 1, which pretty much useless.



Hope that helps,



Ivan

down

-1

Marc ¶

21 years ago

Use ftp_raw() (PHP 5+) instead of ftp_site() if you need the results of the remote command.

down

-1

daemorhedron ¶

22 years ago

I'd like to follow up with Ivan's observation there. Unless I am missing the obvious, which is entirely possible of course, this command is quite useless unless it returns the data from the SITE <foo> request.

Besides the obvious SITE HELP command, another one that would require catching the feedback would be the SITE LOCATE | SITE SEARCH commands. I completely recognize that SITE <foo> commands are indeed insanely proprietary, but the fact still remains that changing this to return the results, or at least having the option to do so (such as exec() and the like) would be vastly preferred to the current method of returning true/false values.

Thanks.

down

-3

webmaster at beezm dot net ¶

21 years ago

I wrote some functions for an ftp server for windows called GuildFTPd.

Here they are, they are pretty much so self explanitory:
<?
function guildftpd_adduser($ftp_stream,$group,$username,$password){
    ftp_site($ftp_stream,"SITE ADDUSER $group $username $password");
}
function guildftpd_addgroup($ftp_stream,$groupname){
    ftp_site($ftp_stream,"SITE ADDGROUP $groupname");
}
function guildftpd_deluser($ftp_stream,$username){
    ftp_site($ftp_stream,"SITE DELUSER $username");
}
function guildftpd_addpath($ftp_stream,$username,$path,$vpath){
    ftp_site($ftp_stream,"SITE ADDPATH $username $path $vpath");
}
function guildftpd_delpath($ftp_stream,$username,$path,$vpath){
    ftp_site($ftp_stream,"SITE DELPATH $username $path $vpath");
}
function guildftpd_anon($ftp_stream){
    ftp_site($ftp_stream,"SITE ANON ALLOW");
}
function guildftpd_anond($ftp_stream){
    ftp_site($ftp_stream,"SITE ANON DENY");
}
function guildftpd_chpass($ftp_stream,$user,$pass){
    ftp_site($ftp_stream,"SITE CHPASS $user $pass");
}
function guildftpd_disable($ftp_stream,$user){
    ftp_site($ftp_stream,"SITE DISABLE $user");
}
function guildftpd_enable($ftp_stream,$user){
    ftp_site($ftp_stream,"SITE ENABLE $user");
}
function guildftpd_who($ftp_stream){
    $who = ftp_site($ftp_stream,"SITE WHO");
}
function guildftpd_kick($ftp_stream,$user);
    ftp_site($ftp_stream,"SITE KICK $user");
}
function guildftpd_msg($ftp_stream,$text);
    ftp_site($ftp_stream,"SITE MSG $text");
}
?>

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