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    User Contributed Notes 33 notes

    up
    112
    sep16 at psu dot edu
    12 years ago
    You can easily parse command line arguments into the $_GET variable by using the parse_str() function.

    <?php

    parse_str    (implode('&', array_slice($argv, 1)), $_GET);

    ?>

    It behaves exactly like you'd expect with cgi-php.

    $ php -f somefile.php a=1 b[]=2 b[]=3

    This will set $_GET['a'] to '1' and $_GET['b'] to array('2', '3').

    Even better, instead of putting that line in every file, take advantage of PHP's auto_prepend_file directive. Put that line in its own file and set the auto_prepend_file directive in your cli-specific php.ini like so:

    auto_prepend_file = "/etc/php/cli-php5.3/local.prepend.php"

    It will be automatically prepended to any PHP file run from the command line.
    up
    19
    apmuthu at usa dot net
    6 years ago
    Adding a pause() function to PHP waiting for any user input returning it:

    <?php
    function pause() {
    $handle = fopen ("php://stdin","r");
    do {     $line = fgets($handle); } while ($line == '');
    fclose($handle);
    return     $line;
    }
    ?>
    up
    25
    frankNospamwanted at. toppoint dot. de
    10 years ago
    Parsing commandline argument GET String without changing the PHP script (linux shell):
    URL: index.php?a=1&b=2
    Result: output.html

    echo "" | php -R 'include("index.php");' -B 'parse_str($argv[1], $_GET);' 'a=1&b=2' >output.html

    (no need to change php.ini)

    You can put this
    echo "" | php -R 'include("'$1'");' -B 'parse_str($argv[1], $_GET);' "$2"
    in a bash script "php_get" to use it like this:
    php_get index.php 'a=1&b=2' >output.html
    or directed to text browser...
    php_get index.php 'a=1&b=2' |w3m -T text/html
    up
    18
    lucas dot vasconcelos at gmail dot com
    17 years ago
    Just another variant of previous script that group arguments doesn't starts with '-' or '--'

    <?php
    function arguments($argv) {
    $_ARG = array();
    foreach (    $argv as $arg) {
    if (    ereg('--([^=]+)=(.*)',$arg,$reg)) {
    $_ARG[$reg[1]] = $reg[2];
    } elseif(    ereg('^-([a-zA-Z0-9])',$arg,$reg)) {
    $_ARG[$reg[1]] = 'true';
    } else {
    $_ARG['input'][]=$arg;
    }
    }
    return     $_ARG;
    }

    print_r(arguments($argv));
    ?>

    $ php myscript.php --user=nobody /etc/apache2/*
    Array
    (
    [input] => Array
    (
    [0] => myscript.php
    [1] => /etc/apache2/apache2.conf
    [2] => /etc/apache2/conf.d
    [3] => /etc/apache2/envvars
    [4] => /etc/apache2/httpd.conf
    [5] => /etc/apache2/mods-available
    [6] => /etc/apache2/mods-enabled
    [7] => /etc/apache2/ports.conf
    [8] => /etc/apache2/sites-available
    [9] => /etc/apache2/sites-enabled
    )

    [user] => nobody
    )
    up
    14
    PSIKYO at mail dot dlut dot edu dot cn
    11 years ago
    If you edit a php file in windows, upload and run it on linux with command line method. You may encounter a running problem probably like that:

    [root@ItsCloud02 wsdl]# ./lnxcli.php
    Extension './lnxcli.php' not present.

    Or you may encounter some other strange problem.
    Care the enter key. In windows environment, enter key generate two binary characters '0D0A'. But in Linux, enter key generate just only a 'OA'.
    I wish it can help someone if you are using windows to code php and run it as a command line program on linux.
    up
    15
    ohcc at 163 dot com
    8 years ago
    use " instead of ' on windows when using the cli version with -r

    php -r "echo 1"
    -- correct

    php -r 'echo 1'
    PHP Parse error: syntax error, unexpected ''echo' (T_ENCAPSED_AND_WHITESPACE), expecting end of file in Command line code on line 1
    up
    19
    drewish at katherinehouse dot com
    19 years ago
    When you're writing one line php scripts remember that 'php://stdin' is your friend. Here's a simple program I use to format PHP code for inclusion on my blog:

    UNIX:
    cat test.php | php -r "print htmlentities(file_get_contents('php://stdin'));"

    DOS/Windows:
    type test.php | php -r "print htmlentities(file_get_contents('php://stdin'));"
    up
    17
    monte at ispi dot net
    21 years ago
    I had a problem with the $argv values getting split up when they contained plus (+) signs. Be sure to use the CLI version, not CGI to get around it.

    Monte
    up
    20
    Kodeart
    13 years ago
    Check directly without calling functions:
    <?php
    if (PHP_SAPI === 'cli')
    {
    // ...
    }
    ?>

    You can define a constant to use it elsewhere
    <?php
    define    ('ISCLI', PHP_SAPI === 'cli');
    ?>
    up
    15
    Anonymous
    3 years ago
    We can pass many arguments directly into the hashbang line.
    As example many ini setting via the -d parameter of php.
    ---
    #!/usr/bin/php -d memory_limit=2048M -d post_max_size=0
    phpinfo();
    exit;
    ---
    ./script | grep memory
    memory_limit => 2048M => 2048M
    ---
    But we can also use this behaviour into a second script, so it call the first as an interpreter, via the hashbang:
    ---
    #!./script arg1 arg2 arg3
    ---
    However the parameters are dispatched in a different way into $argv

    All the parameters are in $argv[1], $argv[0] is the interpreter script name, and $argv[1] is the caller script name.

    To get back the parameters into $argv, we can simply test if $argv[1] contains spaces, and then dispatch again as normal:

    #!/usr/bin/php -d memory_limit=2048M -d post_max_size=0
    <?php
    var_dump    ($argv);
    if (    strpos($argv[1], ' ') !== false){
    $argw = explode(" ", $argv[1]);
    array_unshift($argw, $argv[2]);
    $argv = $argw;
    }
    var_dump($argv); ?>
    ---
    array(3) {
    [0]=>
    string(8) "./script"
    [1]=>
    string(15) "arg1 arg2 arg3 "
    [2]=>
    string(14) "./other_script"
    }
    array(4) {
    [0]=>
    string(8) "./other_script"
    [1]=>
    string(4) "arg1"
    [2]=>
    string(4) "arg2"
    [3]=>
    string(4) "arg3"
    }
    ---
    This will maintain the same behaviour in all cases and allow to even double click a script to call both parameters of another script, and even make a full interpreter language layer. The other script doesn't has to be php. Take care of paths.
    up
    26
    ben at slax0rnet dot com
    20 years ago
    Just a note for people trying to use interactive mode from the commandline.

    The purpose of interactive mode is to parse code snippits without actually leaving php, and it works like this:

    [root@localhost php-4.3.4]# php -a
    Interactive mode enabled

    <?php echo "hi!"; ?>
    <note, here we would press CTRL-D to parse everything we've entered so far>
    hi!
    <?php exit(); ?>
    <ctrl-d here again>
    [root@localhost php-4.3.4]#

    I noticed this somehow got ommited from the docs, hope it helps someone!
    up
    21
    notreallyanaddress at somerandomaddr dot com
    14 years ago
    If you want to be interactive with the user and accept user input, all you need to do is read from stdin.

    <?php
    echo "Are you sure you want to do this? Type 'yes' to continue: ";
    $handle = fopen ("php://stdin","r");
    $line = fgets($handle);
    if(    trim($line) != 'yes'){
    echo     "ABORTING!\n";
    exit;
    }
    echo     "\n";
    echo     "Thank you, continuing...\n";
    ?>
    up
    15
    OverFlow636 at gmail dot com
    19 years ago
    I needed this, you proly wont tho.
    puts the exicution args into $_GET
    <?php
    if ($argv) {
    foreach (    $argv as $k=>$v)
    {
    if (    $k==0) continue;
    $it = explode("=",$argv[$i]);
    if (isset(    $it[1])) $_GET[$it[0]] = $it[1];
    }
    }
    ?>
    up
    7
    sam marshall
    5 years ago
    When using the -R flag, the name of the variable containing the content of the current line (not including the LF) is $argn.

    For example you can do this code:

    cat file.txt | php -R 'echo $argn . "\n";'

    This will just output each line of the input file without doing anything to it.
    up
    16
    thomas dot harding at laposte dot net
    16 years ago
    Parsing command line: optimization is evil!

    One thing all contributors on this page forgotten is that you can suround an argv with single or double quotes. So the join coupled together with the preg_match_all will always break that :)

    Here is a proposal:

    #!/usr/bin/php
    <?php
    print_r    (arguments($argv));

    function     arguments ( $args )
    {
    array_shift( $args );
    $endofoptions = false;

    $ret = array
    (
    'commands' => array(),
    'options' => array(),
    'flags' => array(),
    'arguments' => array(),
    );

    while (     $arg = array_shift($args) )
    {

    // if we have reached end of options,
    //we cast all remaining argvs as arguments
    if ($endofoptions)
    {
    $ret['arguments'][] = $arg;
    continue;
    }

    // Is it a command? (prefixed with --)
    if ( substr( $arg, 0, 2 ) === '--' )
    {

    // is it the end of options flag?
    if (!isset ($arg[3]))
    {
    $endofoptions = true;; // end of options;
    continue;
    }

    $value = "";
    $com = substr( $arg, 2 );

    // is it the syntax '--option=argument'?
    if (strpos($com,'='))
    list(    $com,$value) = split("=",$com,2);

    // is the option not followed by another option but by arguments
    elseif (strpos($args[0],'-') !== 0)
    {
    while (    strpos($args[0],'-') !== 0)
    $value .= array_shift($args).' ';
    $value = rtrim($value,' ');
    }

    $ret['options'][$com] = !empty($value) ? $value : true;
    continue;

    }

    // Is it a flag or a serial of flags? (prefixed with -)
    if ( substr( $arg, 0, 1 ) === '-' )
    {
    for (    $i = 1; isset($arg[$i]) ; $i++)
    $ret['flags'][] = $arg[$i];
    continue;
    }

    // finally, it is not option, nor flag, nor argument
    $ret['commands'][] = $arg;
    continue;
    }

    if (!    count($ret['options']) && !count($ret['flags']))
    {
    $ret['arguments'] = array_merge($ret['commands'], $ret['arguments']);
    $ret['commands'] = array();
    }
    return     $ret;
    }

    exit (    0)

    /* vim: set expandtab tabstop=2 shiftwidth=2: */
    ?>
    up
    11
    rob
    17 years ago
    i use emacs in c-mode for editing. in 4.3, starting a cli script like so:

    #!/usr/bin/php -q /* -*- c -*- */
    <?php

    told emacs to drop into c    -mode automatically when i loaded the file for editing. the '-q' flag didn't actually do anything (in the older cgi versions, it suppressed html output when the script was run) but it caused the commented mode line to be ignored by php.

    in 5.2, '    -q' has apparently been deprecated. replace it with '--' to achieve the 4.3 invocation-with-emacs-mode-line behavior:

    #!/usr/bin/php -- /* -*- c -*- */
    <?php

    don'    t go back to your 4.3 system and replace '-q' with '--'; it seems to cause php to hang waiting on STDIN...
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    9
    Anonymous
    14 years ago
    Using CLI (on WIN at least), some INI paths are relative to the current working directory. For example, if your error_log = "php_errors.log", then php_errors.log will be created (or appended to if already exists) in whatever directory you happen to be in at the moment if you have write access there. Instead of having random error logs all over the place because of this behavior, you may want to set error_log to a full path, perhaps to the php.exe directory.
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    9
    jeff at noSpam[] dot genhex dot net
    22 years ago
    You can also call the script from the command line after chmod'ing the file (ie: chmod 755 file.php).

    On your first line of the file, enter "#!/usr/bin/php" (or to wherever your php executable is located). If you want to suppress the PHP headers, use the line of "#!/usr/bin/php -q" for your path.
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    10
    goalain eat gmail dont com
    17 years ago
    If your php script doesn't run with shebang (#!/usr/bin/php),
    and it issues the beautifull and informative error message:
    "Command not found." just dos2unix yourscript.php
    et voila.

    If you still get the "Command not found."
    Just try to run it as ./myscript.php , with the "./"
    if it works - it means your current directory is not in the executable search path.

    If your php script doesn't run with shebang (#/usr/bin/php),
    and it issues the beautifull and informative message:
    "Invalid null command." it's probably because the "!" is missing in the the shebang line (like what's above) or something else in that area.

    \Alon
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    8
    roberto dot dimas at gmail dot com
    19 years ago
    One of the things I like about perl and vbscripts, is the fact that I can name a file e.g. 'test.pl' and just have to type 'test, without the .pl extension' on the windows command line and the command processor knows that it is a perl file and executes it using the perl command interpreter.

    I did the same with the file extension .php3 (I will use php3 exclusivelly for command line php scripts, I'm doing this because my text editor VIM 6.3 already has the correct syntax highlighting for .php3 files ).

    I modified the PATHEXT environment variable in Windows XP, from the " 'system' control panel applet->'Advanced' tab->'Environment Variables' button-> 'System variables' text area".

    Then from control panel "Folder Options" applet-> 'File Types' tab, I added a new file extention (php3), using the button 'New' and typing php3 in the window that pops up.

    Then in the 'Details for php3 extention' area I used the 'Change' button to look for the Php.exe executable so that the php3 file extentions are associated with the php executable.

    You have to modify also the 'PATH' environment variable, pointing to the folder where the php executable is installed

    Hope this is useful to somebody
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    7
    phpnotes at ssilk dot de
    22 years ago
    To hand over the GET-variables in interactive mode like in HTTP-Mode (e.g. your URI is myprog.html?hugo=bla&bla=hugo), you have to call

    php myprog.html '&hugo=bla&bla=hugo'

    (two & instead of ? and &!)

    There just a little difference in the $ARGC, $ARGV values, but I think this is in those cases not relevant.
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    7
    losbrutos at free dot fr
    17 years ago
    an another "another variant" :

    <?php
    function arguments($argv)
    {
    $_ARG = array();
    foreach (    $argv as $arg)
    {
    if (    preg_match('#^-{1,2}([a-zA-Z0-9]*)=?(.*)$#', $arg, $matches))
    {
    $key = $matches[1];
    switch (    $matches[2])
    {
    case     '':
    case     'true':
    $arg = true;
    break;
    case     'false':
    $arg = false;
    break;
    default:
    $arg = $matches[2];
    }
    $_ARG[$key] = $arg;
    }
    else
    {
    $_ARG['input'][] = $arg;
    }
    }
    return     $_ARG;
    }
    ?>

    $php myscript.php arg1 -arg2=val2 --arg3=arg3 -arg4 --arg5 -arg6=false

    Array
    (
    [input] => Array
    (
    [0] => myscript.php
    [1] => arg1
    )

    [arg2] => val2
    [arg3] => arg3
    [arg4] => true
    [arg5] => true
    [arg5] => false
    )
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    10
    eric dot brison at anakeen dot com
    17 years ago
    Just a variant of previous script to accept arguments with '=' also
    <?php
    function arguments($argv) {
    $_ARG = array();
    foreach (    $argv as $arg) {
    if (    ereg('--([^=]+)=(.*)',$arg,$reg)) {
    $_ARG[$reg[1]] = $reg[2];
    } elseif(    ereg('-([a-zA-Z0-9])',$arg,$reg)) {
    $_ARG[$reg[1]] = 'true';
    }

    }
    return     $_ARG;
    }
    ?>
    $ php myscript.php --user=nobody --password=secret -p --access="host=127.0.0.1 port=456"
    Array
    (
    [user] => nobody
    [password] => secret
    [p] => true
    [access] => host=127.0.0.1 port=456
    )
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    9
    linn at backendmedia dot com
    20 years ago
    For those of you who want the old CGI behaviour that changes to the actual directory of the script use:
    chdir(dirname($_SERVER['argv'][0]));

    at the beginning of your scripts.
    up
    9
    Adam, php(at)getwebspace.com
    21 years ago
    Ok, I've had a heck of a time with PHP > 4.3.x and whether to use CLI vs CGI. The CGI version of 4.3.2 would return (in browser):
    ---
    No input file specified.
    ---

    And the CLI version would return:
    ---
    500 Internal Server Error
    ---

    It appears that in CGI mode, PHP looks at the environment variable PATH_TRANSLATED to determine the script to execute and ignores command line. That is why in the absensce of this environment variable, you get "No input file specified." However, in CLI mode the HTTP headers are not printed. I believe this is intended behavior for both situations but creates a problem when you have a CGI wrapper that sends environment variables but passes the actual script name on the command line.

    By modifying my CGI wrapper to create this PATH_TRANSLATED environment variable, it solved my problem, and I was able to run the CGI build of 4.3.2
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    7
    docey
    19 years ago
    dunno if this is on linux the same but on windows evertime
    you send somthing to the console screen php is waiting for
    the console to return. therefor if you send a lot of small
    short amounts of text, the console is starting to be using
    more cpu-cycles then php and thus slowing the script.

    take a look at this sheme:
    cpu-cycle:1 ->php: print("a");
    cpu-cycle:2 ->cmd: output("a");
    cpu-cycle:3 ->php: print("b");
    cpu-cycle:4 ->cmd: output("b");
    cpu-cycle:5 ->php: print("c");
    cpu-cycle:6 ->cmd: output("c");
    cpu-cylce:7 ->php: print("d");
    cpu-cycle:8 ->cmd: output("d");
    cpu-cylce:9 ->php: print("e");
    cpu-cycle:0 ->cmd: output("e");

    on the screen just appears "abcde". but if you write
    your script this way it will be far more faster:
    cpu-cycle:1 ->php: ob_start();
    cpu-cycle:2 ->php: print("abc");
    cpu-cycle:3 ->php: print("de");
    cpu-cycle:4 ->php: $data = ob_get_contents();
    cpu-cycle:5 ->php: ob_end_clean();
    cpu-cycle:6 ->php: print($data);
    cpu-cycle:7 ->cmd: output("abcde");

    now this is just a small example but if you are writing an
    app that is outputting a lot to the console, i.e. a text
    based screen with frequent updates, then its much better
    to first cach all output, and output is as one big chunk of
    text instead of one char a the time.

    ouput buffering is ideal for this. in my script i outputted
    almost 4000chars of info and just by caching it first, it
    speeded up by almost 400% and dropped cpu-usage.

    because what is being displayed doesn't matter, be it 2
    chars or 40.0000 chars, just the call to output takes a
    great deal of time. remeber that.

    maybe someone can test if this is the same on unix-based
    systems. it seems that the STDOUT stream just waits for
    the console to report ready, before continueing execution.
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    6
    obfuscated at emailaddress dot com
    19 years ago
    This posting is not a php-only problem, but hopefully will save someone a few hours of headaches. Running on MacOS (although this could happen on any *nix I suppose), I was unable to get the script to execute without specifically envoking php from the command line:

    [macg4:valencia/jobs] tim% test.php
    ./test.php: Command not found.

    However, it worked just fine when php was envoked on the command line:

    [macg4:valencia/jobs] tim% php test.php
    Well, here we are... Now what?

    Was file access mode set for executable? Yup.

    [macg4:valencia/jobs] tim% ls -l
    total 16
    -rwxr-xr-x 1 tim staff 242 Feb 24 17:23 test.php

    And you did, of course, remember to add the php command as the first line of your script, yeah? Of course.

    #!/usr/bin/php
    <?php print "Well, here we are... Now what?\n"; ?>

    So why dudn't it work? Well, like I said... on a Mac.... but I also occasionally edit the files on my Windows portable (i.e. when I'm travelling and don't have my trusty Mac available)... Using, say, WordPad on Windows... and BBEdit on the Mac...

    Aaahhh... in BBEdit check how the file is being saved! Mac? Unix? or Dos? Bingo. It had been saved as Dos format. Change it to Unix:

    [macg4:valencia/jobs] tim% ./test.php
    Well, here we are... Now what?
    [macg4:valencia/jobs] tim%

    NB: If you're editing your php files on multiple platforms (i.e. Windows and Linux), make sure you double check the files are saved in a Unix format... those \r's and \n's 'll bite cha!
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    5
    bluej100@gmail
    17 years ago
    In 5.1.2 (and others, I assume), the -f form silently drops the first argument after the script name from $_SERVER['argv']. I'd suggest avoiding it unless you need it for a special case.
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    5
    Alexander Plakidin
    21 years ago
    How to change current directory in PHP script to script's directory when running it from command line using PHP 4.3.0?
    (you'll probably need to add this to older scripts when running them under PHP 4.3.0 for backwards compatibility)

    Here's what I am using:
    chdir(preg_replace('/\\/[^\\/]+$/',"",$PHP_SELF));

    Note: documentation says that "PHP_SELF" is not available in command-line PHP scripts. Though, it IS available. Probably this will be changed in future version, so don't rely on this line of code...

    Use $_SERVER['PHP_SELF'] instead of just $PHP_SELF if you have register_globals=Off
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    4
    Popeye at P-t-B dot com
    21 years ago
    In *nix systems, use the WHICH command to show the location of the php binary executable. This is the path to use as the first line in your php shell script file. (#!/path/to/php -q) And execute php from the command line with the -v switch to see what version you are running.

    example:

    # which php
    /usr/local/bin/php
    # php -v
    PHP 4.3.1 (cli) (built: Mar 27 2003 14:41:51)
    Copyright (c) 1997-2002 The PHP Group
    Zend Engine v1.3.0, Copyright (c) 1998-2002 Zend Technologies

    In the above example, you would use: #!/usr/local/bin/php

    Also note that, if you do not have the current/default directory in your PATH (.), you will have to use ./scriptfilename to execute your script file from the command line (or you will receive a "command not found" error). Use the ENV command to show your PATH environment variable value.
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    5
    stromdotcom at hotmail dot com
    18 years ago
    Spawning php-win.exe as a child process to handle scripting in Windows applications has a few quirks (all having to do with pipes between Windows apps and console apps).

    To do this in C++:

    // We will run php.exe as a child process after creating
    // two pipes and attaching them to stdin and stdout
    // of the child process
    // Define sa struct such that child inherits our handles

    SECURITY_ATTRIBUTES sa = { sizeof(SECURITY_ATTRIBUTES) };
    sa.bInheritHandle = TRUE;
    sa.lpSecurityDescriptor = NULL;

    // Create the handles for our two pipes (two handles per pipe, one for each end)
    // We will have one pipe for stdin, and one for stdout, each with a READ and WRITE end
    HANDLE hStdoutRd, hStdoutWr, hStdinRd, hStdinWr;

    // Now create the pipes, and make them inheritable
    CreatePipe (&hStdoutRd, &hStdoutWr, &sa, 0))
    SetHandleInformation(hStdoutRd, HANDLE_FLAG_INHERIT, 0);
    CreatePipe (&hStdinRd, &hStdinWr, &sa, 0)
    SetHandleInformation(hStdinWr, HANDLE_FLAG_INHERIT, 0);

    // Now we have two pipes, we can create the process
    // First, fill out the usage structs
    STARTUPINFO si = { sizeof(STARTUPINFO) };
    PROCESS_INFORMATION pi;
    si.dwFlags = STARTF_USESTDHANDLES;
    si.hStdOutput = hStdoutWr;
    si.hStdInput = hStdinRd;

    // And finally, create the process
    CreateProcess (NULL, "c:\\php\\php-win.exe", NULL, NULL, TRUE, NORMAL_PRIORITY_CLASS, NULL, NULL, &si, &pi);

    // Close the handles we aren't using
    CloseHandle(hStdoutWr);
    CloseHandle(hStdinRd);

    // Now that we have the process running, we can start pushing PHP at it
    WriteFile(hStdinWr, "<?php echo 'test'; ?>", 9, &dwWritten, NULL);

    // When we're done writing to stdin, we close that pipe
    CloseHandle(hStdinWr);

    // Reading from stdout is only slightly more complicated
    int i;

    std::string processed("");
    char buf[128];

    while ( (ReadFile(hStdoutRd, buf, 128, &dwRead, NULL) && (dwRead != 0)) ) {
    for (i = 0; i < dwRead; i++)
    processed += buf[i];
    }

    // Done reading, so close this handle too
    CloseHandle(hStdoutRd);

    A full implementation (implemented as a C++ class) is available at http://www.stromcode.com
    up
    3
    pyxl at jerrell dot com
    22 years ago
    Assuming --prefix=/usr/local/php, it's better to create a symlink from /usr/bin/php or /usr/local/bin/php to target /usr/local/php/bin/php so that it's both in your path and automatically correct every time you rebuild. If you forgot to do that copy of the binary after a rebuild, you can do all kinds of wild goose chasing when things break.
    up
    2
    james_s2010 at NOSPAM dot hotmail dot com
    17 years ago
    I was looking for a way to interactively get a single character response from user. Using STDIN with fread, fgets and such will only work after pressing enter. So I came up with this instead:

    #!/usr/bin/php -q
    <?php
    function inKey($vals) {
    $inKey = "";
    While(!    in_array($inKey,$vals)) {
    $inKey = trim(`read -s -n1 valu;echo \$valu`);
    }
    return     $inKey;
    }
    function     echoAT($Row,$Col,$prompt="") {
    // Display prompt at specific screen coords
    echo "\033[".$Row.";".$Col."H".$prompt;
    }
    // Display prompt at position 10,10
    echoAT(10,10,"Opt : ");

    // Define acceptable responses
    $options = array("1","2","3","4","X");

    // Get user response
    $key = inKey($options);

    // Display user response & exit
    echoAT(12,10,"Pressed : $key\n");
    ?>

    Hope this helps someone.
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