PHP 8.4.0 RC4 available for testing

ibase_gen_id

(PHP 5, PHP 7 < 7.4.0)

ibase_gen_idIncrémente le générateur donné et retourne sa nouvelle valeur

Description

ibase_gen_id(string $generator, int $increment = 1, resource $link_identifier = null): mixed
Avertissement

Cette fonction est actuellement non documentée ; seule la liste des arguments est disponible.

Valeurs de retour

Retourne une nouvelle valeur générée sous la forme d'un entier ou d'une chaîne de caractères si la valeur est trop grosse.

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User Contributed Notes 3 notes

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-1
robert
17 years ago
EXAMPLE:
You need to know the generator´s value after INSERT:

Before INSERT-Statement run

$nextnumber=ibase_gen_id ("GEN_NAME",1);

GEN_NAME: is the generator´s name

1: means add 1 to actual value of generator

$nextnumber: is variable to store generators value after incrementing

In the INSERT-Statement you can use $nextnumber instead of using generator directly like in:
INSERT INTO test (field1, field2) VALUES gen_id(gen_test_id, 1), 'testme');
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-3
escoric at latinmail dot com
20 years ago
$sql="INSERT INTO mitabla(campo1,campo2,..campo n) VALUES(GEN_ID(mitabla1_codigo_gen,1),'contenido 1', 'contenido 2', 'contenido n' )";
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-4
mfischer at php dot net
20 years ago
Question arose on php-dev:

How does ibase_gen_id() handle 64bit values?

Interbase 6/Firebird generators are always 64-bit signed integers
(Firebird's BIGINT type), regardless of the platform the client is
running.
On 64-bit platforms, this will never require conversion as PHP's int
type is 64 bits wide on those platforms. On 32-bit platforms, the
generated value is converted to a string if it exceeds the limits of a
32-bit signed integer.
(This behaviour is consistent with the ibase_fetch_*() functions, that
will use strings to represent numerical values that cannot be represented
accurately using native PHP numerical types.)

[Edited by PHP/Interbase maintainer.]
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