filter_has_var

(PHP 5 >= 5.2.0, PHP 7, PHP 8)

filter_has_var — 指定した型の変数が存在するかどうかを調べる

説明

filter_has_var(int $input_type, string $var_name): bool

パラメータ

input_type: INPUT_GET、INPUT_POST、 INPUT_COOKIE、INPUT_SERVER、 INPUT_ENV のいずれか。
var_name: 調べたい変数の名前。

戻り値

成功した場合に true を、失敗した場合に false を返します。

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User Contributed Notes 2 notes

down

drm at melp dot nl ¶

15 years ago

Please note that the function does not check the live array, it actually checks the content received by php:

<?php
$_GET['test'] = 1;
echo filter_has_var(INPUT_GET, 'test') ? 'Yes' : 'No';
?>

would say "No", unless the parameter was actually in the querystring.

Also, if the input var is empty, it will say Yes.

down

nanhe dot kumar at gmail dot com ¶

11 years ago

Through this example i think you can better understand

    if ( !filter_has_var(INPUT_GET, 'email') ) {
        echo "Email Not Found";
    }else{
        echo "Email Found";
    }
    Output

    localhost/nanhe/test.php?email=1 //Email Found
    localhost/nanhe/test.php?email //Email Found
    http://localhost/nanhe/test.php //Email Not Found

Consider on second example

http://localhost/nanhe/test.php
$_GET['email']="info@nanhe.in";
if ( !filter_has_var(INPUT_GET, 'email') ) {
        echo "Email Not Found";
    }else{
        echo "Email Found";
    }
But output will be Email Not Found

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