ImagickDraw::pushClipPath

(PECL imagick 2, PECL imagick 3)

ImagickDraw::pushClipPath — クリップパスの定義を開始する

説明

public ImagickDraw::pushClipPath(string $clip_mask_id): bool

警告

この関数は、現在のところ詳細な情報はありません。引数のリストのみが記述されています。

クリップパスの定義を開始します。これは、任意の数の描画コマンドで構成され、最後は ImagickDraw::popClipPath() コマンドとなります。

パラメータ

clip_mask_id: クリップマスク ID。

戻り値

値を返しません。

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User Contributed Notes 1 note

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bogdan at moongate dot ro ¶

13 years ago

Here's an interactive example for your enjoyment, featuring two intersecting discs. My version doesn't antialias the clipping path; I suppose YMMV.



<?php



// Simple clip path example

// Bogdan Stancescu



$showClipping=1; // Try setting this to 0!

$showDrawing=1;  // Try setting this to 0!



// Don't edit below this line (at least until you understand the example)



$showBoth=$showClipping && $showDrawing;

$showAny=$showClipping || $showDrawing;



$image=new Imagick(); // Create image



// Image size

$width=151;

$height=101;



$image->newImage($width, $height, new ImagickPixel('lightgray')); // some visible background



$draw=new ImagickDraw(); // Create draw object



if ($showBoth)

        $draw->pushClipPath('circle_left'); // Start clipping path



if ($showClipping) {

        $draw->setFillColor('red'); // The color doesn't matter if we clip

        $draw->circle(50,50,50,0); // A circle that occupies 100x100px on the left

}



if ($showBoth) {

        $draw->popClipPath(); // Finish clipping path

        $draw->setClipPath('circle_left'); // Use the clipping path above

}



if ($showDrawing) {

        $draw->setFillColor('navy'); // This is the actual drawing color

        $draw->circle(100,50,100,0); // A circle that occupies 100x100px on the right

}



if ($showAny)

        $image->drawImage($draw); // Render $draw unto $image



$image->setImageFormat('png'); // Tell ImageMagick how to render this

header("Content-Type: image/png"); // Tell the browser how to render this



echo $image; // Render the image into the browser

?>

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