PHP 8.4.1 Released!

mysqli::$info

mysqli_info

(PHP 5, PHP 7, PHP 8)

mysqli::$info -- mysqli_info直近に実行されたクエリの情報を取得する

説明

オブジェクト指向型

手続き型

mysqli_info(mysqli $mysql): ?string

mysqli_info() 関数は、直近に実行されたクエリに ついての情報を文字列で返します。文字列の詳細は以下のとおりです。

mysqli_info のとりうる戻り値
クエリの型 結果文字列の例
INSERT INTO...SELECT... Records: 100 Duplicates: 0 Warnings: 0
INSERT INTO...VALUES (...),(...),(...) Records: 3 Duplicates: 0 Warnings: 0
LOAD DATA INFILE ... Records: 1 Deleted: 0 Skipped: 0 Warnings: 0
ALTER TABLE ... Records: 3 Duplicates: 0 Warnings: 0
UPDATE ... Rows matched: 40 Changed: 40 Warnings: 0

注意:

これらのどれにも当てはまらない形式のクエリはサポートされません。 そのような場合、mysqli_info() は空文字列を返します。

パラメータ

link

手続き型のみ: mysqli_connect() あるいは mysqli_init() が返す mysqliオブジェクト。

戻り値

直近に実行されたクエリについての追加情報を文字列で返します。

例1 $mysqli->info の例

オブジェクト指向型

<?php

mysqli_report
(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");

$mysqli->query("CREATE TEMPORARY TABLE t1 LIKE City");

/* INSERT INTO ... SELECT */
$mysqli->query("INSERT INTO t1 SELECT * FROM City ORDER BY ID LIMIT 150");
printf("%s\n", $mysqli->info);

手続き型

<?php

mysqli_report
(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$link = mysqli_connect("localhost", "my_user", "my_password", "world");

mysqli_query($link, "CREATE TEMPORARY TABLE t1 LIKE City");

/* INSERT INTO ... SELECT */
mysqli_query($link, "INSERT INTO t1 SELECT * FROM City ORDER BY ID LIMIT 150");
printf("%s\n", mysqli_info($link));

上の例の出力は以下となります。

Records: 150  Duplicates: 0  Warnings: 0

参考

add a note

User Contributed Notes 3 notes

up
26
user at biglake dot com
13 years ago
Might save someone some time...

<?php
$prototype
='Rows matched: 0 Changed: 1 Warnings: 2';
list(
$matched, $changed, $warnings) = sscanf($prototype, "Rows matched: %d Changed: %d Warnings: %d");
?>
up
0
Rumour
5 months ago
I don't recall where I got this, but it is SUPER important information and I cannot believe it is missing from the documentation!

If you do a mysqli_info()/$mysqli->info() after a "INSERT INTO ... VALUES ()" that adds/updates JUST ONE ROW, then, mysqli::info() returns an empty result (!!!).

If it is empty (null on php 8+; in php 7 I don't know in which way it is empty) check $mysqli->affectedRows() or mysqli_affected_rows(). If that returns 2, the INSERT did a successful UPDATE of ONE record (so there must have been a ON DUPLICATE KEY UPDATE). If it returns 1: there was an INSERT of ONE record.

This is not a bug, this is BY DESIGN, although it does remind me strongly of "This is not a bug, this is a feature" Microsoft of the 90's. I have no clue why you would design it this way except for some weird and extremely old backward compatibility issues.
up
0
vzverev [at] newmail.ru (Vasiliy Zverev)
7 years ago
If inserted just one row, mysqli_info() returns empty string which might be confusing, but mysqli_affected_rows() returns 1 in this case.
To Top