If you want to convert an integer into an English word string, eg. 29 -> twenty-nine, then here's a function to do it.Note on use of fmod() I used the floating point fmod() in preference to the % operator, because % converts the operands to int, corrupting values outside of the range [-2147483648, 2147483647]I haven't bothered with "billion" because the word means 10e9 or 10e12 depending who you ask.The function returns '#' if the argument does not represent a whole number.<?php$nwords = array( "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen", "twenty", 30 => "thirty", 40 => "forty", 50 => "fifty", 60 => "sixty", 70 => "seventy", 80 => "eighty", 90 => "ninety" );function int_to_words($x) { global $nwords; if(!is_numeric($x)) $w = '#'; else if(fmod($x, 1) != 0) $w = '#'; else { if($x < 0) { $w = 'minus '; $x = -$x; } else $w = ''; if($x < 21) $w .= $nwords[$x]; else if($x < 100) { $w .= $nwords[10 * floor($x/10)]; $r = fmod($x, 10); if($r > 0) $w .= '-'. $nwords[$r]; } else if($x < 1000) { $w .= $nwords[floor($x/100)] .' hundred'; $r = fmod($x, 100); if($r > 0) $w .= ' and '. int_to_words($r); } else if($x < 1000000) { $w .= int_to_words(floor($x/1000)) .' thousand'; $r = fmod($x, 1000); if($r > 0) { $w .= ' '; if($r < 100) $w .= 'and '; $w .= int_to_words($r); } } else { $w .= int_to_words(floor($x/1000000)) .' million'; $r = fmod($x, 1000000); if($r > 0) { $w .= ' '; if($r < 100) $word .= 'and '; $w .= int_to_words($r); } } } return $w;}?>Usage:<?phpecho 'There are currently '. int_to_words($count) . ' members logged on.';?>