PHP 8.4.0 RC4 available for testing

Imagick::rotateImage

(PECL imagick 2, PECL imagick 3)

Imagick::rotateImageGörüntüyü döndürür

Açıklama

public Imagick::rotateImage(mixed $artalan, float $açı): bool

Görüntüyü açı derece döndürür. Görüntünün döndürülmesiyle boşalan üçgenler artalan rengiyle doldurulur.

Bağımsız Değişkenler

artalan

Artalan rengi.

açı

Derece cinsinden dönme açısı.

Dönen Değerler

Başarı durumunda true döner.

Sürüm Bilgisi

Sürüm: Açıklama
PECL imagick 2.1.0 Artık renk olarak rengi ifade eden bir dizge belirtilebiliyor. Evvelce sadece bir ImagickPixel nesnesi belirtilebiliyordu.

Örnekler

Örnek 1 - Imagick::rotateImage() örneği

<?php
function rotateImage($imagePath, $angle, $color) {
$imagick = new \Imagick(realpath($imagePath));
$imagick->rotateimage($color, $angle);
header("Content-Type: image/jpg");
echo
$imagick->getImageBlob();
}

?>

add a note

User Contributed Notes 4 notes

up
5
gleb dot deykalo at gmail dot com
8 years ago
Some transformations including Imagick ::rotateImage() may change "image page" -- working area inside the image you work on.

Be careful with future modifications afterwards because the image page would be different from new sizes of the image.

For example, if you do Imagic::cropImage() after rotation, you need to set image page properly, otherwise your crop would be performed relating to wrong coordinates (depending on rotation angle, resulting image size may vary).

<?php
$Image
= new Imagick($sourceImagePath);

$transparent = '#00000000';
$Image->rotateImage(new \ImagickPixel(), 45); // This makes resulting image bigger

// Set page to be of the full size of new image, starting at top left corner (0, 0)
$Image->setImagePage($Image->getImageWidth(), $Image->getImageHeight(), 0, 0);

$Image->cropImage($crop_w, $crop_h, $crop_x, $crop_y);
?>
up
4
Anonymous
8 years ago
The degrees for imagick and gd is difference!
GD > rotate 90 means counter clockwise.
Imagick > rotate 90 means clockwise.

GD 90 = Imagick 270 or Imagick 90 = GD 270.

Use this function.

<?php
function calculateCounterClockwise($value)
{
if (
$value == 0 || $value == 180) {
return
$value;
}
if (
$value < 0 || $value > 360) {
$value = 90;
}

$total_degree = 360;
$output = intval($total_degree-$value);
return
$output;
}
// calculateCounterClockwise

echo '1 = '.calculateCounterClockwise(1).'<br>';
echo
'90 = '.calculateCounterClockwise(90).'<br>';
echo
'270 = '.calculateCounterClockwise(270).'<br>';
echo
'359 = '.calculateCounterClockwise(359).'<br>';
echo
'360 = '.calculateCounterClockwise(360).'<br>';
?>

test results:
1 = 359
90 = 270
270 = 90
359 = 1
360 = 0
up
2
AlexG
12 years ago
Transparent

<?php $im->rotateImage(new ImagickPixel('#00000000'), 75); ?>
up
1
wjsams at gmail dot com
15 years ago
If you want to rotate an image by a certain degree you can do this:

<?php
header
('content-type: image/jpeg');
$imagick = new Imagick();
$imagick->readImage('castle.jpg');
$imagick->rotateImage(new ImagickPixel(), 90);
print
$imagick->getImage();
?>
To Top