is_a

(PHP 4 >= 4.2.0, PHP 5, PHP 7, PHP 8)

is_aChecks whether the object is of a given type or subtype

Опис

is_a(mixed $object_or_class, string $class, bool $allow_string = false): bool

Determines if the given object_or_class is the class object type, or has class as one of its supertypes.

Параметри

object_or_class

A class name or an object instance.

class

The class or interface name

allow_string

If this parameter set to false, string class name as object_or_class is not allowed. This also prevents from calling autoloader if the class doesn't exist.

Значення, що повертаються

Returns true if object_or_class is the class object type, or has class as one of its supertypes, false otherwise.

Приклади

Приклад #1 is_a() example

<?php
// define a class
class WidgetFactory
{
var
$oink = 'moo';
}

// create a new object
$WF = new WidgetFactory();

if (
is_a($WF, 'WidgetFactory')) {
echo
"yes, \$WF is still a WidgetFactory\n";
}
?>

Приклад #2 Using the instanceof operator

<?php
// define a class
class WidgetFactory
{
var
$oink = 'moo';
}

// create a new object
$WF = new WidgetFactory();

if (
$WF instanceof WidgetFactory) {
echo
'Yes, $WF is a WidgetFactory';
}
?>

Прогляньте також

  • get_class() - Returns the name of the class of an object
  • get_parent_class() - Retrieves the parent class name for object or class
  • is_subclass_of() - Checks if the object has this class as one of its parents or implements it

add a note

User Contributed Notes 7 notes

up
66
Ronald Locke
8 years ago
Please note that you have to fully qualify the class name in the second parameter. A use statement will not resolve namespace dependencies in that is_a() function. <?php namespace foo\bar;class A {};class B extends A {};?><?phpnamespace har\var;use foo\bar\A;$foo = new foo\bar\B();is_a($foo, 'A'); // returns false;is_a($foo, 'foo\bar\A'); // returns true;?>Just adding that note here because all examples are without namespaces.
up
34
Aron Budinszky
13 years ago
Be careful! Starting in PHP 5.3.7 the behavior of is_a() has changed slightly: when calling is_a() with a first argument that is not an object, __autoload() is triggered!In practice, this means that calling is_a('23', 'User'); will trigger __autoload() on "23". Previously, the above statement simply returned 'false'.More info can be found here:https://bugs.php.net/bug.php?id=55475Whether this change is considered a bug and whether it will be reverted or kept in future versions is yet to be determined, but nevertheless it is how it is, for now...
up
18
p dot scheit at zweipol dot net
18 years ago
At least in PHP 5.1.6 this works as well with Interfaces.<?phpinterface test {  public function A();}class TestImplementor implements test {  public function A () {    print "A";  }}$testImpl = new TestImplementor();var_dump(is_a($testImpl,'test'));?>will return true
up
4
SlimDeluxe
2 years ago
For anyone wondering, this does not work with traits :(
up
11
cesoid at yahoo dot com
19 years ago
is_a returns TRUE for instances of children of the class.For example:class Animal{}class Dog extends Animal{}$test = new Dog();In this example is_a($test, "Animal") would evaluate to TRUE as well as is_a($test, "Dog").This seemed intuitive to me, but did not seem to be documented.
up
2
dkrupyanskiy[at]gmail
7 years ago
Looks like the function signature given in description is wrong. Actually it can take a string  as a first parameter in the case if $allow_string is set to true. It took some time to find out how the last parameter should be used. Please consider the following example<?phpclass Foo{}spl_autoload_register(    function($classname){        printf('autoload has been triggered for %s%s', $classname, PHP_EOL);    });var_dump(is_a('UndefinedClassName', Foo::class, true));?>
up
2
eitan at mosenkis dot net
13 years ago
As of PHP 5.3.9, is_a() seems to return false when passed a string for the first argument. Instead, use is_subclass_of() and, if necessary for your purposes, also check if the two arguments are equal, since is_subclass_of('foo', 'foo') will return false, while is_a('foo', 'foo') used to return true.
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