If you need an easy way to convert a decimal julian day to an unix timestamp you can use:
$unixTimeStamp = ($julianDay - 2440587.5) * 86400;
2440587.5 is the julian day at 1/1/1970 0:00 UTC
86400 is the number of seconds in a day
(PHP 4, PHP 5, PHP 7, PHP 8)
jdtounix — Convert Julian Day to Unix timestamp
This function will return a Unix timestamp corresponding to the
Julian Day given in julian_day. The time returned is
UTC.
julian_day
A julian day number between 2440588 and 106751993607888
on 64bit systems, or between 2440588 and 2465443 on 32bit systems.
The unix timestamp for the start (midnight, not noon) of the given Julian day
If julian_day is outside of the allowed range,
a ValueError is thrown.
| Версія | Опис |
|---|---|
| 8.0.0 |
This function no longer returns false on failure, but raises a
ValueError instead.
|
| 7.3.24, 7.4.12 |
The upper limit of julian_day has been extended. Previously,
it was 2465342 regardless of the architecture.
|
If you need an easy way to convert a decimal julian day to an unix timestamp you can use:
$unixTimeStamp = ($julianDay - 2440587.5) * 86400;
2440587.5 is the julian day at 1/1/1970 0:00 UTC
86400 is the number of seconds in a dayWarning: the calender functions involving julian day operations seem to ignore the decimal part of the julian day count.
This means that the returned date is wrong 50% of the time, since a julian day starts at decimal .5 . Take care!!Remember that unixtojd() assumes your timestamp is in GMT, but jdtounix() returns a timestamp in localtime.
This fooled me a few times.
So if you have:
$timestamp1 = time();
$timestamp2 = jdtounix(unixtojd($timestamp1));
Unless your localtime is the same as GMT, $timestamp1 will not equal $timestamp2.Remember that UNIX timestamps indicate a number of seconds from midnight of January 1, 1970 on the Gregorian calendar, not the Julian Calendar.unixtojd() assumes that your timestamp is in GMT, but jdtounix() returns a timestamp in localtime.
so
<?php
$d1=jdtogregorian(unixtojd(time()));
$d2= gmdate("m/d/Y");
$d3=date("m/d/Y");
?>
$d1 always equals $d2 but $d1 may differ from $d3