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mysql_result

(PHP 4, PHP 5)

mysql_resultGet result data

Увага

Це розширення застаріле, починаючи з PHP 5.5.0, та вилучене з PHP 7.0.0. Натомість використовуються розширення MySQLi або PDO_MySQL. Докладніше описано у керівництві MySQL: вибір API. Цю функцію можна замінити на:

Опис

mysql_result(resource $result, int $row, mixed $field = 0): string

Retrieves the contents of one cell from a MySQL result set.

When working on large result sets, you should consider using one of the functions that fetch an entire row (specified below). As these functions return the contents of multiple cells in one function call, they're MUCH quicker than mysql_result(). Also, note that specifying a numeric offset for the field argument is much quicker than specifying a fieldname or tablename.fieldname argument.

Параметри

result

Результат типу resource для опрацювання, якого повертає функція mysql_query().

row

The row number from the result that's being retrieved. Row numbers start at 0.

field

The name or offset of the field being retrieved.

It can be the field's offset, the field's name, or the field's table dot field name (tablename.fieldname). If the column name has been aliased ('select foo as bar from...'), use the alias instead of the column name. If undefined, the first field is retrieved.

Значення, що повертаються

The contents of one cell from a MySQL result set on success, or false on failure.

Приклади

Приклад #1 mysql_result() example

<?php
$link
= mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!
$link) {
die(
'Could not connect: ' . mysql_error());
}
if (!
mysql_select_db('database_name')) {
die(
'Could not select database: ' . mysql_error());
}
$result = mysql_query('SELECT name FROM work.employee');
if (!
$result) {
die(
'Could not query:' . mysql_error());
}
echo
mysql_result($result, 2); // outputs third employee's name

mysql_close($link);
?>

Примітки

Зауваження:

Calls to mysql_result() should not be mixed with calls to other functions that deal with the result set.

Прогляньте також

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User Contributed Notes 4 notes

up
18
freedman at FreeFormIT dot com
9 years ago
here's a rough replacement using mysqli:

if (!function_exists('mysql_result')) {
function mysql_result($result, $number, $field=0) {
mysqli_data_seek($result, $number);
$row = mysqli_fetch_array($result);
return $row[$field];
}
}
up
1
bob dot schuon at loungelizard dot com
4 years ago
This function accounts for the ability of the original function to accept "table_name.field_name" entries as well as just the field name:

function mysqli_result($res, $row, $field=0) {
$result->data_seek($row);
$data = $result->fetch_array();
$field_name = $field;
if ( is_string($field) ) {
$fields_array = explode(".", $field);
$array_len = count($fields_array);
if ($array_len > 1) {
$field_name = $fields_array[array_len - 1];
} else {
$field_name = $fields_array[0];
}
}

return $data[$field_name];
}
up
1
mark at pnod dot co dot uk
1 year ago
To replace a row count e.g.

$querystring = "SELECT COUNT(*) FROM table WHERE column1 = 'EXAMPLE'";
$total_records = mysql_result(mysql_query($querystring,$connection),0);

use mysqli_fetch_row :

$querystring = "SELECT COUNT(*) FROM table WHERE column1 = 'EXAMPLE'";
$rowcount = mysqli_fetch_row(mysqli_query($connection,$querystring));
$total_records = $rowcount[0];
up
-3
v dot teemu at gmail dot com
8 years ago
I was also looking for mysqli replacement for getting first row, when query is known to return just 1 value. It seems this is simple:

echo(mysql_result($result, 0));

becomes

echo($result->fetch_row()[0]);

alternatively

if ($row = $result->fetch_row()) {
echo($row[0]);
}
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