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jdtofrench

(PHP 4, PHP 5, PHP 7, PHP 8)

jdtofrenchConverte do calendário "Julian Day Count" para o calendário Republicano Francês

Descrição

jdtofrench(int $julian_day): string

Converte do calendário "Julian Day Count" para o calendário Republicano Francês

Parâmetros

julian_day

Um número de data Juliana como inteiro

Valor Retornado

A data republicana francesa como uma string no formato "mês/dia/ano"

Veja Também

  • frenchtojd() - Converte uma data do calendário Republicano Francês para uma contagem de Dias Julianos
  • cal_from_jd() - Converte de uma Contagem de Dias Julianos para um calendário suportado

+adicione uma nota

Notas Enviadas por Usuários (em inglês) 4 notes

up
2
pieterc dot depraetere at ugent dot be
14 years ago
If you want to convert a date later than September 22nd 1806, you could use this function. It's a bit crude and due to the fact the original function terminates in the middle of 1806, it uses 1805 as it's 'terminus post quem'.
<?php
function extended_jdtofrench ($juliandate) {
if (
$juliandate > 2380945) {
// jdtofrench () only accepts dates until september 1806
$gregorian_date = jdtogregorian ($juliandate);
$temp = explode ('/', $gregorian_date);
$year = $temp[2];
$juliandate = gregoriantojd ($temp[0], $temp[1], 1805);
$republican_date = jdtofrench ($juliandate);
$republican_date = explode ('/', $republican_date);
$diff = $year - 1805;
$republican_date[2] = $republican_date[2] + $diff;
} else {
$republican_date = jdtofrench ($juliandate);
}
return
$republican_date;
}
?>
up
1
squenz at titania dot bottoms-dream dot de
18 years ago
Here is a small piece of code to obtain the string data for a correctly converted gregorian date:

<?php
$arDateFrench
= gregorian2FrenchDateArray(11, 9, 1799) ;

echo
$arDateFrench[1] . " " . $arDateFrench[0] . " " . $arDateFrench[2] ;

/* the output will be:
18 Brumaire VIII

*/

function gregorian2FrenchDateArray($m, $d, $y)
{

$julian_date = gregoriantojd($m, $d, $y);
$french = jdtofrench($julian_date);
if(
$french == "0/0/0")
return
"" ;

$arD = split("/", $french) ;

// get the month name
$monthname = FrenchMonthNames($arD[0]) ;

/* convert the year number to roman digits (as most historians do and documents of the time did */
$stryear = decrom($arD[2]) ;
return array(
$monthname, $arD[1], $stryear ) ;
}

function
FrenchMonthNames($mo)
{
/* The names have been invented by Fabre d'Églantine, a second or rather third rank poet
of primarily pastoral poems, with each name referring to the respective period in the agricultural year; e.g. "Vendémiaire" (approx. September) is derived from "vendange" ("harvest"), "Brumaire" (Ocotober/November) from "brume" ("fog") and so on ... */


$arMo = array("Vendémiaire",
"Brumaire",
"Frimaire",
"Nivôse",
"Pluviôse",
"Ventôse",
"Germinal",
"Floréal",
"Prairial",
"Messidor",
"Thermidor",
"Fructidor",
"Sansculottide") ;

if(
$mo < count($arMo)+1)
return
$arMo[$mo-1] ;

}

function
decrom($dec){
$digits=array(
1 => "I",
4 => "IV",
5 => "V",
9 => "IX",
10 => "X",
40 => "XL",
50 => "L",
90 => "XC",
100 => "C",
400 => "CD",
500 => "D",
900 => "CM",
1000 => "M"
);
krsort($digits);
$retval="";
foreach(
$digits as $key => $value){
while(
$dec>=$key){
$dec-=$key;
$retval.=$value;
}
}
return
$retval;
}
?>
up
0
popy-dev
6 years ago
Also note that there are few date converters handling French calendar outside the jdtofrench covered range.
up
-2
serged at noos dot fr
21 years ago
Very limited function:

(extract from source of 4.3.3)
These routines only convert dates in years 1 through 14 (Gregorian dates 22 September 1792 through 22 September 1806). This more than covers the period when the calendar was in use.

Pour les français :
Ces routines ne converitssent les dates que de l'an 1 à 14 (du 22 septembre 1792 au 22 septembre 1806). Cela couvre plus que la période pendant laquelle le calendrier à été utilisé.
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