If you need an easy way to convert a decimal julian day to an unix timestamp you can use:$unixTimeStamp = ($julianDay - 2440587.5) * 86400;2440587.5 is the julian day at 1/1/1970 0:00 UTC86400 is the number of seconds in a day
(PHP 4, PHP 5, PHP 7, PHP 8)
jdtounix — Converte Dia Juliano para timestamp Unix
Esta função irá retorna um timestamp Unix correspondente ao
Dia Juliano especificado no parâmetro julian_day. O horário retornado é
UTC.
julian_day
O número de dia juliano entre 2440588 e 106751993607888
em sistemas de 64 bits, ou entre 2440588 e 2465443 em sistemas de 32 bits
O timestamp Unix para o início (meia noite, não meio dia) do dia juliano informado
Se julian_day estiver fora do intervalo permitido,
um ValueError é lançado.
| Versão | Descrição |
|---|---|
| 8.0.0 |
Essa funcão não retorna mais false em caso de falha, mas lança um
ValueError.
|
| 7.3.24, 7.4.12 |
O limite superior de julian_day foi extendido. Antes,
era 2465342 sem levar a arquitetura em consideração.
|
If you need an easy way to convert a decimal julian day to an unix timestamp you can use:$unixTimeStamp = ($julianDay - 2440587.5) * 86400;2440587.5 is the julian day at 1/1/1970 0:00 UTC86400 is the number of seconds in a dayWarning: the calender functions involving julian day operations seem to ignore the decimal part of the julian day count.This means that the returned date is wrong 50% of the time, since a julian day starts at decimal .5 . Take care!!Remember that unixtojd() assumes your timestamp is in GMT, but jdtounix() returns a timestamp in localtime.This fooled me a few times. So if you have:$timestamp1 = time();$timestamp2 = jdtounix(unixtojd($timestamp1));Unless your localtime is the same as GMT, $timestamp1 will not equal $timestamp2.Remember that UNIX timestamps indicate a number of seconds from midnight of January 1, 1970 on the Gregorian calendar, not the Julian Calendar.unixtojd() assumes that your timestamp is in GMT, but jdtounix() returns a timestamp in localtime.so<?php$d1=jdtogregorian(unixtojd(time()));$d2= gmdate("m/d/Y");$d3=date("m/d/Y");?>$d1 always equals $d2 but $d1 may differ from $d3